Solve 2a+2b+3-a-a-b-2

$$2a+2b+3-a-a-b-2$$

Evaluate

$$b+1$$

Solution Steps

Combine 2a and -a to get a.

$$a+2b+3-a-b-2$$

Combine a and -a to get 0.

$$2b+3-b-2$$

Combine 2b and -b to get b.

$$b+3-2$$

Subtract 2 from 3 to get 1.

$$b+1$$

Differentiate w.r.t. b

$$1$$

Steps Using Derivative Rule for Sum

Combine 2a and -a to get a.

$$\frac{\mathrm{d}}{\mathrm{d}b}(a+2b+3-a-b-2)$$

Combine a and -a to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}b}(2b+3-b-2)$$

Combine 2b and -b to get b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(b+3-2)$$

Subtract 2 from 3 to get 1.

$$\frac{\mathrm{d}}{\mathrm{d}b}(b+1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$b^{1-1}$$

Subtract 1 from 1.

$$b^{0}$$

For any term t except 0, t^{0}=1.

$$1$$