Solve for a
a=\frac{\sqrt{3b}+5}{2}
b\geq 0
Solve for b
b=\frac{\left(2a-5\right)^{2}}{3}
a\geq \frac{5}{2}
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2a=\sqrt{3b}+5
The equation is in standard form.
\frac{2a}{2}=\frac{\sqrt{3b}+5}{2}
Divide both sides by 2.
a=\frac{\sqrt{3b}+5}{2}
Dividing by 2 undoes the multiplication by 2.
\sqrt{3b}+5=2a
Swap sides so that all variable terms are on the left hand side.
\sqrt{3b}=2a-5
Subtract 5 from both sides.
3b=\left(2a-5\right)^{2}
Square both sides of the equation.
\frac{3b}{3}=\frac{\left(2a-5\right)^{2}}{3}
Divide both sides by 3.
b=\frac{\left(2a-5\right)^{2}}{3}
Dividing by 3 undoes the multiplication by 3.
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