Solve for A
A=\frac{83+5C-7B}{2}
Solve for B
B=\frac{83+5C-2A}{7}
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2A-5C=83-7B
Subtract 7B from both sides.
2A=83-7B+5C
Add 5C to both sides.
2A=83+5C-7B
The equation is in standard form.
\frac{2A}{2}=\frac{83+5C-7B}{2}
Divide both sides by 2.
A=\frac{83+5C-7B}{2}
Dividing by 2 undoes the multiplication by 2.
7B-5C=83-2A
Subtract 2A from both sides.
7B=83-2A+5C
Add 5C to both sides.
7B=83+5C-2A
The equation is in standard form.
\frac{7B}{7}=\frac{83+5C-2A}{7}
Divide both sides by 7.
B=\frac{83+5C-2A}{7}
Dividing by 7 undoes the multiplication by 7.
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