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28\times 2=x\left(x+10\right)
Multiply both sides by 2.
56=x\left(x+10\right)
Multiply 28 and 2 to get 56.
56=x^{2}+10x
Use the distributive property to multiply x by x+10.
x^{2}+10x=56
Swap sides so that all variable terms are on the left hand side.
x^{2}+10x-56=0
Subtract 56 from both sides.
x=\frac{-10±\sqrt{10^{2}-4\left(-56\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 10 for b, and -56 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-10±\sqrt{100-4\left(-56\right)}}{2}
Square 10.
x=\frac{-10±\sqrt{100+224}}{2}
Multiply -4 times -56.
x=\frac{-10±\sqrt{324}}{2}
Add 100 to 224.
x=\frac{-10±18}{2}
Take the square root of 324.
x=\frac{8}{2}
Now solve the equation x=\frac{-10±18}{2} when ± is plus. Add -10 to 18.
x=4
Divide 8 by 2.
x=-\frac{28}{2}
Now solve the equation x=\frac{-10±18}{2} when ± is minus. Subtract 18 from -10.
x=-14
Divide -28 by 2.
x=4 x=-14
The equation is now solved.
28\times 2=x\left(x+10\right)
Multiply both sides by 2.
56=x\left(x+10\right)
Multiply 28 and 2 to get 56.
56=x^{2}+10x
Use the distributive property to multiply x by x+10.
x^{2}+10x=56
Swap sides so that all variable terms are on the left hand side.
x^{2}+10x+5^{2}=56+5^{2}
Divide 10, the coefficient of the x term, by 2 to get 5. Then add the square of 5 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+10x+25=56+25
Square 5.
x^{2}+10x+25=81
Add 56 to 25.
\left(x+5\right)^{2}=81
Factor x^{2}+10x+25. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+5\right)^{2}}=\sqrt{81}
Take the square root of both sides of the equation.
x+5=9 x+5=-9
Simplify.
x=4 x=-14
Subtract 5 from both sides of the equation.