Solve 28mquadtext{(b)}14mquadtext{(c)}21m

$$28 m \quad \text { (b) } 14 m \quad \text { (c) } 21 m$$

Evaluate

$$8232bcm^{3}$$

Solution Steps

Multiply m and m to get m^{2}.

$$28m^{2}b\times 14c\times 21m$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$28m^{3}b\times 14c\times 21$$

Multiply 28 and 14 to get 392.

$$392m^{3}bc\times 21$$

Multiply 392 and 21 to get 8232.

$$8232m^{3}bc$$

Differentiate w.r.t. b

$$8232cm^{3}$$