Solve for x
x\geq \frac{14}{3}
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\frac{28}{6}\leq x
Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.
\frac{14}{3}\leq x
Reduce the fraction \frac{28}{6} to lowest terms by extracting and canceling out 2.
x\geq \frac{14}{3}
Swap sides so that all variable terms are on the left hand side. This changes the sign direction.
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