Solve 28div(-7)(2)^2+3(-4-2)^2-(-3)^2

$$28 \div ( - 7 ) ( 2 ) ^ { 2 } + 3 ( - 4 - 2 ) ^ { 2 } - ( - 3 ) ^ { 2 }$$

Evaluate

$$83$$

Solution Steps

Divide 28 by -7 to get -4.

$$-4\times 2^{2}+3\left(-4-2\right)^{2}-\left(-3\right)^{2}$$

Calculate 2 to the power of 2 and get 4.

$$-4\times 4+3\left(-4-2\right)^{2}-\left(-3\right)^{2}$$

Multiply -4 and 4 to get -16.

$$-16+3\left(-4-2\right)^{2}-\left(-3\right)^{2}$$

Subtract 2 from -4 to get -6.

$$-16+3\left(-6\right)^{2}-\left(-3\right)^{2}$$

Calculate -6 to the power of 2 and get 36.

$$-16+3\times 36-\left(-3\right)^{2}$$

Multiply 3 and 36 to get 108.

$$-16+108-\left(-3\right)^{2}$$

Add -16 and 108 to get 92.

$$92-\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$92-9$$

Subtract 9 from 92 to get 83.

$$83$$

Factor

$$83$$