Solve 28*y=1/x^3+1

$$28 \cdot y = \frac { 1 } { x ^ { 3 } + 1 }$$

Solve for y

$$y=\frac{1}{28\left(x^{3}+1\right)}$$

$$x\neq -1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by \left(x+1\right)\left(x^{2}-x+1\right).

$$28y\left(x+1\right)\left(x^{2}-x+1\right)=1$$

Use the distributive property to multiply 28y by x+1.

$$\left(28yx+28y\right)\left(x^{2}-x+1\right)=1$$

Use the distributive property to multiply 28yx+28y by x^{2}-x+1 and combine like terms.

$$28yx^{3}+28y=1$$

Combine all terms containing y.

$$\left(28x^{3}+28\right)y=1$$

Divide both sides by 28x^{3}+28.

$$\frac{\left(28x^{3}+28\right)y}{28x^{3}+28}=\frac{1}{28x^{3}+28}$$

Dividing by 28x^{3}+28 undoes the multiplication by 28x^{3}+28.

$$y=\frac{1}{28x^{3}+28}$$

Divide 1 by 28x^{3}+28.

$$y=\frac{1}{28\left(x+1\right)\left(x^{2}-x+1\right)}$$

Solve for x

$$x=\frac{28^{\frac{2}{3}}\sqrt[3]{-28+\frac{1}{y}}}{28}$$

$$y\neq 0$$