Solve 28^2+x^2=(x+14)^2

$$28 ^ { 2 } + x ^ { 2 } = ( x + 14 ) ^ { 2 }$$

Solve for x

$$x=21$$

Steps for Solving Linear Equation

Calculate 28 to the power of 2 and get 784.

$$784+x^{2}=\left(x+14\right)^{2}$$

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+14\right)^{2}.

$$784+x^{2}=x^{2}+28x+196$$

Subtract x^{2} from both sides.

$$784+x^{2}-x^{2}=28x+196$$

Combine x^{2} and -x^{2} to get 0.

$$784=28x+196$$

Swap sides so that all variable terms are on the left hand side.

$$28x+196=784$$

Subtract 196 from both sides.

$$28x=784-196$$

Subtract 196 from 784 to get 588.

$$28x=588$$

Divide both sides by 28.

$$x=\frac{588}{28}$$

Divide 588 by 28 to get 21.

$$x=21$$