Solve 27(1-2/3)(1-6/3)(1-9/3)

$$27(1- \frac{ 2 }{ 3 } )(1- \frac{ 6 }{ 3 } )(1- \frac{ 9 }{ 3 } )$$

Evaluate

$$18$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$27\left(\frac{3}{3}-\frac{2}{3}\right)\left(1-\frac{6}{3}\right)\left(1-\frac{9}{3}\right)$$

Since \frac{3}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$27\times \frac{3-2}{3}\left(1-\frac{6}{3}\right)\left(1-\frac{9}{3}\right)$$

Subtract 2 from 3 to get 1.

$$27\times \frac{1}{3}\left(1-\frac{6}{3}\right)\left(1-\frac{9}{3}\right)$$

Multiply 27 and \frac{1}{3} to get \frac{27}{3}.

$$\frac{27}{3}\left(1-\frac{6}{3}\right)\left(1-\frac{9}{3}\right)$$

Divide 27 by 3 to get 9.

$$9\left(1-\frac{6}{3}\right)\left(1-\frac{9}{3}\right)$$

Divide 6 by 3 to get 2.

$$9\left(1-2\right)\left(1-\frac{9}{3}\right)$$

Subtract 2 from 1 to get -1.

$$9\left(-1\right)\left(1-\frac{9}{3}\right)$$

Multiply 9 and -1 to get -9.

$$-9\left(1-\frac{9}{3}\right)$$

Divide 9 by 3 to get 3.

$$-9\left(1-3\right)$$

Subtract 3 from 1 to get -2.

$$-9\left(-2\right)$$

Multiply -9 and -2 to get 18.

$$18$$

Factor

$$2\times 3^{2}$$