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y\left(27y^{3}+1\right)
Factor out y.
\left(3y+1\right)\left(9y^{2}-3y+1\right)
Consider 27y^{3}+1. Rewrite 27y^{3}+1 as \left(3y\right)^{3}+1^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
y\left(3y+1\right)\left(9y^{2}-3y+1\right)
Rewrite the complete factored expression. Polynomial 9y^{2}-3y+1 is not factored since it does not have any rational roots.