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\left(3u^{2}-a\right)\left(9u^{4}+3au^{2}+a^{2}\right)
Rewrite 27u^{6}-a^{3} as \left(3u^{2}\right)^{3}-a^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).