Factor
q\left(3q+4\right)\left(9q^{2}-12q+16\right)
Evaluate
q\left(27q^{3}+64\right)
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q\left(27q^{3}+64\right)
Factor out q.
\left(3q+4\right)\left(9q^{2}-12q+16\right)
Consider 27q^{3}+64. Rewrite 27q^{3}+64 as \left(3q\right)^{3}+4^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
q\left(3q+4\right)\left(9q^{2}-12q+16\right)
Rewrite the complete factored expression. Polynomial 9q^{2}-12q+16 is not factored since it does not have any rational roots.
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