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\left(3m^{2}-2n^{2}\right)\left(9m^{4}+6m^{2}n^{2}+4n^{4}\right)
Rewrite 27m^{6}-8n^{6} as \left(3m^{2}\right)^{3}-\left(2n^{2}\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).