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\left(3a-b^{2}\right)\left(9a^{2}+3ab^{2}+b^{4}\right)
Rewrite 27a^{3}-b^{6} as \left(3a\right)^{3}-\left(b^{2}\right)^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).