Solve 27^frac{1{3}}*8^2/3*125^-3*16^-frac{1{4}}=

$$27 ^ { \frac { 1 } { 3 } } \times 8 ^ { 2 / 3 } \times 125 ^ { - 3 } \times 16 ^ { - \frac { 1 } { 4 } } =$$

Evaluate

$$\frac{6}{1953125}=0.000003072$$

Solution Steps

Calculate 27 to the power of \frac{1}{3} and get 3.

$$3\times 8^{\frac{2}{3}}\times 125^{-3}\times 16^{-\frac{1}{4}}$$

Calculate 8 to the power of \frac{2}{3} and get 4.

$$3\times 4\times 125^{-3}\times 16^{-\frac{1}{4}}$$

Multiply 3 and 4 to get 12.

$$12\times 125^{-3}\times 16^{-\frac{1}{4}}$$

Calculate 125 to the power of -3 and get \frac{1}{1953125}.

$$12\times \frac{1}{1953125}\times 16^{-\frac{1}{4}}$$

Multiply 12 and \frac{1}{1953125} to get \frac{12}{1953125}.

$$\frac{12}{1953125}\times 16^{-\frac{1}{4}}$$

Calculate 16 to the power of -\frac{1}{4} and get \frac{1}{2}.

$$\frac{12}{1953125}\times \frac{1}{2}$$

Multiply \frac{12}{1953125} and \frac{1}{2} to get \frac{6}{1953125}.

$$\frac{6}{1953125}$$

Factor

$$\frac{2 \cdot 3}{5 ^ {9}} = 3.072 \times 10^{-6}$$