Solve for x
x=\frac{6y-3}{25}
Solve for y
y=\frac{25x}{6}+\frac{1}{2}
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25x+3=6y
Add 6y to both sides. Anything plus zero gives itself.
25x=6y-3
Subtract 3 from both sides.
\frac{25x}{25}=\frac{6y-3}{25}
Divide both sides by 25.
x=\frac{6y-3}{25}
Dividing by 25 undoes the multiplication by 25.
-6y+3=-25x
Subtract 25x from both sides. Anything subtracted from zero gives its negation.
-6y=-25x-3
Subtract 3 from both sides.
\frac{-6y}{-6}=\frac{-25x-3}{-6}
Divide both sides by -6.
y=\frac{-25x-3}{-6}
Dividing by -6 undoes the multiplication by -6.
y=\frac{25x}{6}+\frac{1}{2}
Divide -25x-3 by -6.
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Limits
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