Solve 2500P+120N=23

$$2500 P + 120 N = 23$$

Solve for N

$$N=-\frac{125P}{6}+\frac{23}{120}$$

Steps for Solving Linear Equation

Subtract 2500P from both sides.

$$120N=23-2500P$$

Divide both sides by 120.

$$\frac{120N}{120}=\frac{23-2500P}{120}$$

Dividing by 120 undoes the multiplication by 120.

$$N=\frac{23-2500P}{120}$$

Divide 23-2500P by 120.

$$N=-\frac{125P}{6}+\frac{23}{120}$$

Solve for P

$$P=-\frac{6N}{125}+\frac{23}{2500}$$

Steps for Solving Linear Equation

Subtract 120N from both sides.

$$2500P=23-120N$$

Divide both sides by 2500.

$$\frac{2500P}{2500}=\frac{23-120N}{2500}$$

Dividing by 2500 undoes the multiplication by 2500.

$$P=\frac{23-120N}{2500}$$

Divide 23-120N by 2500.

$$P=-\frac{6N}{125}+\frac{23}{2500}$$