Solve 25-16-x^2=16-(25-10x+x^2)

$$25-16- { x }^{ 2 } =16-(25-10x+ { x }^{ 2 } )$$

Solve for x

$$x = \frac{9}{5} = 1\frac{4}{5} = 1.8$$

Steps for Solving Linear Equation

Subtract 16 from 25 to get 9.

$$9-x^{2}=16-\left(25-10x+x^{2}\right)$$

To find the opposite of 25-10x+x^{2}, find the opposite of each term.

$$9-x^{2}=16-25+10x-x^{2}$$

Subtract 25 from 16 to get -9.

$$9-x^{2}=-9+10x-x^{2}$$

Subtract 10x from both sides.

$$9-x^{2}-10x=-9-x^{2}$$

Add x^{2} to both sides.

$$9-x^{2}-10x+x^{2}=-9$$

Combine -x^{2} and x^{2} to get 0.

$$9-10x=-9$$

Subtract 9 from both sides.

$$-10x=-9-9$$

Subtract 9 from -9 to get -18.

$$-10x=-18$$

Divide both sides by -10.

$$x=\frac{-18}{-10}$$

Reduce the fraction \frac{-18}{-10} to lowest terms by extracting and canceling out -2.

$$x=\frac{9}{5}$$