Solve 25-frac{3*17-10-6*left(8-4*2-sqrt[3]{27}right)-4*4}{7}

$$25- \frac{ 3 \times 17-10-6 \times \left( 8-4 \times 2- \sqrt[3]{ 27 } \right) -4 \times 4 }{ 7 }$$

Evaluate

$$\frac{132}{7}\approx 18.857142857$$

Solution Steps

Multiply 3 and 17 to get 51.

$$25-\frac{51-10-6\left(8-4\times 2-\sqrt[3]{27}\right)-4\times 4}{7}$$

Subtract 10 from 51 to get 41.

$$25-\frac{41-6\left(8-4\times 2-\sqrt[3]{27}\right)-4\times 4}{7}$$

Multiply 4 and 2 to get 8.

$$25-\frac{41-6\left(8-8-\sqrt[3]{27}\right)-4\times 4}{7}$$

Subtract 8 from 8 to get 0.

$$25-\frac{41-6\left(0-\sqrt[3]{27}\right)-4\times 4}{7}$$

Calculate \sqrt[3]{27} and get 3.

$$25-\frac{41-6\left(0-3\right)-4\times 4}{7}$$

Subtract 3 from 0 to get -3.

$$25-\frac{41-6\left(-3\right)-4\times 4}{7}$$

Multiply 6 and -3 to get -18.

$$25-\frac{41-\left(-18\right)-4\times 4}{7}$$

The opposite of -18 is 18.

$$25-\frac{41+18-4\times 4}{7}$$

Add 41 and 18 to get 59.

$$25-\frac{59-4\times 4}{7}$$

Multiply 4 and 4 to get 16.

$$25-\frac{59-16}{7}$$

Subtract 16 from 59 to get 43.

$$25-\frac{43}{7}$$

Subtract \frac{43}{7} from 25 to get \frac{132}{7}.

$$\frac{132}{7}$$

Factor

$$\frac{2 ^ {2} \cdot 3 \cdot 11}{7} = 18\frac{6}{7} = 18.857142857142858$$