Solve 25(x+5+x+3)=95

$$25(x+5+x+3)=95$$

Solve for x

$$x = -\frac{21}{10} = -2\frac{1}{10} = -2.1$$

Steps for Solving Linear Equation

Divide both sides by 25.

$$x+5+x+3=\frac{95}{25}$$

Reduce the fraction \frac{95}{25} to lowest terms by extracting and canceling out 5.

$$x+5+x+3=\frac{19}{5}$$

Combine x and x to get 2x.

$$2x+5+3=\frac{19}{5}$$

Add 5 and 3 to get 8.

$$2x+8=\frac{19}{5}$$

Subtract 8 from both sides.

$$2x=\frac{19}{5}-8$$

Convert 8 to fraction \frac{40}{5}.

$$2x=\frac{19}{5}-\frac{40}{5}$$

Since \frac{19}{5} and \frac{40}{5} have the same denominator, subtract them by subtracting their numerators.

$$2x=\frac{19-40}{5}$$

Subtract 40 from 19 to get -21.

$$2x=-\frac{21}{5}$$

Divide both sides by 2.

$$x=\frac{-\frac{21}{5}}{2}$$

Express \frac{-\frac{21}{5}}{2} as a single fraction.

$$x=\frac{-21}{5\times 2}$$

Multiply 5 and 2 to get 10.

$$x=\frac{-21}{10}$$

Fraction \frac{-21}{10} can be rewritten as -\frac{21}{10} by extracting the negative sign.

$$x=-\frac{21}{10}$$