Solve 25x-19-[3-(4x-5)]=3x-(6x-5)

$$25 x - 19 - [ 3 - ( 4 x - 5 ) ] = 3 x - ( 6 x - 5 )$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

To find the opposite of 4x-5, find the opposite of each term.

$$25x-19-\left(3-4x-\left(-5\right)\right)=3x-\left(6x-5\right)$$

The opposite of -5 is 5.

$$25x-19-\left(3-4x+5\right)=3x-\left(6x-5\right)$$

Add 3 and 5 to get 8.

$$25x-19-\left(8-4x\right)=3x-\left(6x-5\right)$$

To find the opposite of 8-4x, find the opposite of each term.

$$25x-19-8-\left(-4x\right)=3x-\left(6x-5\right)$$

The opposite of -4x is 4x.

$$25x-19-8+4x=3x-\left(6x-5\right)$$

Subtract 8 from -19 to get -27.

$$25x-27+4x=3x-\left(6x-5\right)$$

Combine 25x and 4x to get 29x.

$$29x-27=3x-\left(6x-5\right)$$

To find the opposite of 6x-5, find the opposite of each term.

$$29x-27=3x-6x-\left(-5\right)$$

The opposite of -5 is 5.

$$29x-27=3x-6x+5$$

Combine 3x and -6x to get -3x.

$$29x-27=-3x+5$$

Add 3x to both sides.

$$29x-27+3x=5$$

Combine 29x and 3x to get 32x.

$$32x-27=5$$

Add 27 to both sides.

$$32x=5+27$$

Add 5 and 27 to get 32.

$$32x=32$$

Divide both sides by 32.

$$x=\frac{32}{32}$$

Divide 32 by 32 to get 1.

$$x=1$$