Solve 25x^2-30x+27

$$25 x ^ { 2 } - 30 x + 27$$

Evaluate

$$25x^{2}-30x+27$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 25

$$x ^ 2 -\frac{6}{5}x +\frac{27}{25} = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = \frac{6}{5} rs = \frac{27}{25}$$

Two numbers r and s sum up to \frac{6}{5} exactly when the average of the two numbers is \frac{1}{2}*\frac{6}{5} = \frac{3}{5}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = \frac{3}{5} - u s = \frac{3}{5} + u$$

To solve for unknown quantity u, substitute these in the product equation rs = \frac{27}{25}

$$(\frac{3}{5} - u) (\frac{3}{5} + u) = \frac{27}{25}$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$\frac{9}{25} - u^2 = \frac{27}{25}$$

Simplify the expression by subtracting \frac{9}{25} on both sides

$$-u^2 = \frac{27}{25}-\frac{9}{25} = \frac{18}{25}$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = -\frac{18}{25} u = \pm\sqrt{-\frac{18}{25}} = \pm \frac{\sqrt{18}}{5}i$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =\frac{3}{5} - \frac{\sqrt{18}}{5}i = 0.600 - 0.849i s = \frac{3}{5} + \frac{\sqrt{18}}{5}i = 0.600 + 0.849i$$

Differentiate w.r.t. x

$$50x-30$$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2\times 25x^{2-1}-30x^{1-1}$$

Multiply 2 times 25.

$$50x^{2-1}-30x^{1-1}$$

Subtract 1 from 2.

$$50x^{1}-30x^{1-1}$$

Subtract 1 from 1.

$$50x^{1}-30x^{0}$$

For any term t, t^{1}=t.

$$50x-30x^{0}$$

For any term t except 0, t^{0}=1.

$$50x-30$$