Solve 25a^2-700a+3300=0

$$25 a ^ { 2 } - 700 a + 3300 = 0$$

Solve for a

$$a=6$$

$$a=22$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$25a^{2}-700a+3300=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 25 for a, -700 for b, and 3300 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{-\left(-700\right)±\sqrt{\left(-700\right)^{2}-4\times 25\times 3300}}{2\times 25}$$

Square -700.

$$a=\frac{-\left(-700\right)±\sqrt{490000-4\times 25\times 3300}}{2\times 25}$$

Multiply -4 times 25.

$$a=\frac{-\left(-700\right)±\sqrt{490000-100\times 3300}}{2\times 25}$$

Multiply -100 times 3300.

$$a=\frac{-\left(-700\right)±\sqrt{490000-330000}}{2\times 25}$$

Add 490000 to -330000.

$$a=\frac{-\left(-700\right)±\sqrt{160000}}{2\times 25}$$

Take the square root of 160000.

$$a=\frac{-\left(-700\right)±400}{2\times 25}$$

The opposite of -700 is 700.

$$a=\frac{700±400}{2\times 25}$$

Multiply 2 times 25.

$$a=\frac{700±400}{50}$$

Now solve the equation a=\frac{700±400}{50} when ± is plus. Add 700 to 400.

$$a=\frac{1100}{50}$$

Divide 1100 by 50.

$$a=22$$

Now solve the equation a=\frac{700±400}{50} when ± is minus. Subtract 400 from 700.

$$a=\frac{300}{50}$$

Divide 300 by 50.

$$a=6$$

The equation is now solved.

$$a=22 a=6$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$25a^{2}-700a+3300=0$$

Subtract 3300 from both sides of the equation.

$$25a^{2}-700a+3300-3300=-3300$$

Subtracting 3300 from itself leaves 0.

$$25a^{2}-700a=-3300$$

Divide both sides by 25.

$$\frac{25a^{2}-700a}{25}=-\frac{3300}{25}$$

Dividing by 25 undoes the multiplication by 25.

$$a^{2}+\left(-\frac{700}{25}\right)a=-\frac{3300}{25}$$

Divide -700 by 25.

$$a^{2}-28a=-\frac{3300}{25}$$

Divide -3300 by 25.

$$a^{2}-28a=-132$$

Divide -28, the coefficient of the x term, by 2 to get -14. Then add the square of -14 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$a^{2}-28a+\left(-14\right)^{2}=-132+\left(-14\right)^{2}$$

Square -14.

$$a^{2}-28a+196=-132+196$$

Add -132 to 196.

$$a^{2}-28a+196=64$$

Factor a^{2}-28a+196. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(a-14\right)^{2}=64$$

Take the square root of both sides of the equation.

$$\sqrt{\left(a-14\right)^{2}}=\sqrt{64}$$

Simplify.

$$a-14=8 a-14=-8$$

Add 14 to both sides of the equation.

$$a=22 a=6$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 25

$$x ^ 2 -28x +132 = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = 28 rs = 132$$

Two numbers r and s sum up to 28 exactly when the average of the two numbers is \frac{1}{2}*28 = 14. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = 14 - u s = 14 + u$$

To solve for unknown quantity u, substitute these in the product equation rs = 132

$$(14 - u) (14 + u) = 132$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$196 - u^2 = 132$$

Simplify the expression by subtracting 196 on both sides

$$-u^2 = 132-196 = -64$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = 64 u = \pm\sqrt{64} = \pm 8$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =14 - 8 = 6 s = 14 + 8 = 22$$