Solve 25(1-x)^2=19

$$25 ( 1 - x ) ^ { 2 } = 19$$

Solve for x

$$x=-\frac{\sqrt{19}}{5}+1\approx 0.128220211$$

$$x=\frac{\sqrt{19}}{5}+1\approx 1.871779789$$

Steps by Finding Square Root

Divide both sides by 25.

$$\frac{25\left(-x+1\right)^{2}}{25}=\frac{19}{25}$$

Dividing by 25 undoes the multiplication by 25.

$$\left(-x+1\right)^{2}=\frac{19}{25}$$

Take the square root of both sides of the equation.

$$-x+1=\frac{\sqrt{19}}{5} -x+1=-\frac{\sqrt{19}}{5}$$

Subtract 1 from both sides of the equation.

$$-x+1-1=\frac{\sqrt{19}}{5}-1 -x+1-1=-\frac{\sqrt{19}}{5}-1$$

Subtracting 1 from itself leaves 0.

$$-x=\frac{\sqrt{19}}{5}-1 -x=-\frac{\sqrt{19}}{5}-1$$

Subtract 1 from \frac{\sqrt{19}}{5}.

$$-x=\frac{\sqrt{19}}{5}-1$$

Subtract 1 from -\frac{\sqrt{19}}{5}.

$$-x=-\frac{\sqrt{19}}{5}-1$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{\frac{\sqrt{19}}{5}-1}{-1} \frac{-x}{-1}=\frac{-\frac{\sqrt{19}}{5}-1}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{\frac{\sqrt{19}}{5}-1}{-1} x=\frac{-\frac{\sqrt{19}}{5}-1}{-1}$$

Divide \frac{\sqrt{19}}{5}-1 by -1.

$$x=-\frac{\sqrt{19}}{5}+1$$

Divide -\frac{\sqrt{19}}{5}-1 by -1.

$$x=\frac{\sqrt{19}}{5}+1$$

The equation is now solved.

$$x=-\frac{\sqrt{19}}{5}+1 x=\frac{\sqrt{19}}{5}+1$$