Solve for b
b=\frac{10}{c}
c\neq 0
Solve for c
c=\frac{10}{b}
b\neq 0
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25\times 2=5bc
Multiply both sides by 2.
50=5bc
Multiply 25 and 2 to get 50.
5bc=50
Swap sides so that all variable terms are on the left hand side.
5cb=50
The equation is in standard form.
\frac{5cb}{5c}=\frac{50}{5c}
Divide both sides by 5c.
b=\frac{50}{5c}
Dividing by 5c undoes the multiplication by 5c.
b=\frac{10}{c}
Divide 50 by 5c.
25\times 2=5bc
Multiply both sides by 2.
50=5bc
Multiply 25 and 2 to get 50.
5bc=50
Swap sides so that all variable terms are on the left hand side.
\frac{5bc}{5b}=\frac{50}{5b}
Divide both sides by 5b.
c=\frac{50}{5b}
Dividing by 5b undoes the multiplication by 5b.
c=\frac{10}{b}
Divide 50 by 5b.
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