Solve 25+6=c^2

$$25 + 6 = c ^ { 2 }$$

Solve for c

$$c=\sqrt{31}\approx 5.567764363$$

$$c=-\sqrt{31}\approx -5.567764363$$

Steps by Finding Square Root

Add 25 and 6 to get 31.

$$31=c^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$c^{2}=31$$

Take the square root of both sides of the equation.

$$c=\sqrt{31} c=-\sqrt{31}$$

Steps Using the Quadratic Formula

Add 25 and 6 to get 31.

$$31=c^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$c^{2}=31$$

Subtract 31 from both sides.

$$c^{2}-31=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -31 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$c=\frac{0±\sqrt{0^{2}-4\left(-31\right)}}{2}$$

Square 0.

$$c=\frac{0±\sqrt{-4\left(-31\right)}}{2}$$

Multiply -4 times -31.

$$c=\frac{0±\sqrt{124}}{2}$$

Take the square root of 124.

$$c=\frac{0±2\sqrt{31}}{2}$$

Now solve the equation c=\frac{0±2\sqrt{31}}{2} when ± is plus.

$$c=\sqrt{31}$$

Now solve the equation c=\frac{0±2\sqrt{31}}{2} when ± is minus.

$$c=-\sqrt{31}$$

The equation is now solved.

$$c=\sqrt{31} c=-\sqrt{31}$$