Solve 25+[3^3div9+[3^2*5-3*(2^3-5^1)]]

$$25 + [ 3 ^ { 3 } \div 9 + [ 3 ^ { 2 } \cdot 5 - 3 \cdot ( 2 ^ { 3 } - 5 ^ { 1 } ) ] ]$$

Evaluate

$$64$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$25+\frac{27}{9}+3^{2}\times 5-3\left(2^{3}-5^{1}\right)$$

Divide 27 by 9 to get 3.

$$25+3+3^{2}\times 5-3\left(2^{3}-5^{1}\right)$$

Add 25 and 3 to get 28.

$$28+3^{2}\times 5-3\left(2^{3}-5^{1}\right)$$

Calculate 3 to the power of 2 and get 9.

$$28+9\times 5-3\left(2^{3}-5^{1}\right)$$

Multiply 9 and 5 to get 45.

$$28+45-3\left(2^{3}-5^{1}\right)$$

Calculate 2 to the power of 3 and get 8.

$$28+45-3\left(8-5^{1}\right)$$

Calculate 5 to the power of 1 and get 5.

$$28+45-3\left(8-5\right)$$

Subtract 5 from 8 to get 3.

$$28+45-3\times 3$$

Multiply 3 and 3 to get 9.

$$28+45-9$$

Subtract 9 from 45 to get 36.

$$28+36$$

Add 28 and 36 to get 64.

$$64$$

Factor

$$2^{6}$$