Solve 24b^3p^3div(-3pb^2)

$$24 b ^ { 3 } p ^ { 3 } \div ( - 3 p b ^ { 2 } )$$

Evaluate

$$-8bp^{2}$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{24^{1}b^{3}p^{3}}{\left(-3\right)^{1}b^{2}p^{1}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{24^{1}}{\left(-3\right)^{1}}b^{3-2}p^{3-1}$$

Subtract 2 from 3.

$$\frac{24^{1}}{\left(-3\right)^{1}}b^{1}p^{3-1}$$

Subtract 1 from 3.

$$\frac{24^{1}}{\left(-3\right)^{1}}bp^{2}$$

Divide 24 by -3.

$$-8bp^{2}$$

Differentiate w.r.t. p

$$-16bp$$