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3\left(8-q^{3}\right)
Factor out 3.
\left(q-2\right)\left(-q^{2}-2q-4\right)
Consider 8-q^{3}. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 8 and q divides the leading coefficient -1. One such root is 2. Factor the polynomial by dividing it by q-2.
3\left(q-2\right)\left(-q^{2}-2q-4\right)
Rewrite the complete factored expression. Polynomial -q^{2}-2q-4 is not factored since it does not have any rational roots.