Solve 2300+40x-80=1500+120x-80

$$2300+40x-80=1500+120x-80$$

Solve for x

$$x=10$$

Steps for Solving Linear Equation

Subtract 80 from 2300 to get 2220.

$$2220+40x=1500+120x-80$$

Subtract 80 from 1500 to get 1420.

$$2220+40x=1420+120x$$

Subtract 120x from both sides.

$$2220+40x-120x=1420$$

Combine 40x and -120x to get -80x.

$$2220-80x=1420$$

Subtract 2220 from both sides.

$$-80x=1420-2220$$

Subtract 2220 from 1420 to get -800.

$$-80x=-800$$

Divide both sides by -80.

$$x=\frac{-800}{-80}$$

Divide -800 by -80 to get 10.

$$x=10$$