Solve 225div5^2+(4/15-3/5)-3^3=

$$225 \div { 5 }^{ 2 } +( \frac{ 4 }{ 15 } - \frac{ 3 }{ 5 } )- { 3 }^{ 3 } =$$

Evaluate

$$-\frac{55}{3}\approx -18.333333333$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\frac{225}{25}+\frac{4}{15}-\frac{3}{5}-3^{3}$$

Divide 225 by 25 to get 9.

$$9+\frac{4}{15}-\frac{3}{5}-3^{3}$$

Convert 9 to fraction \frac{135}{15}.

$$\frac{135}{15}+\frac{4}{15}-\frac{3}{5}-3^{3}$$

Since \frac{135}{15} and \frac{4}{15} have the same denominator, add them by adding their numerators.

$$\frac{135+4}{15}-\frac{3}{5}-3^{3}$$

Add 135 and 4 to get 139.

$$\frac{139}{15}-\frac{3}{5}-3^{3}$$

Least common multiple of 15 and 5 is 15. Convert \frac{139}{15} and \frac{3}{5} to fractions with denominator 15.

$$\frac{139}{15}-\frac{9}{15}-3^{3}$$

Since \frac{139}{15} and \frac{9}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{139-9}{15}-3^{3}$$

Subtract 9 from 139 to get 130.

$$\frac{130}{15}-3^{3}$$

Reduce the fraction \frac{130}{15} to lowest terms by extracting and canceling out 5.

$$\frac{26}{3}-3^{3}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{26}{3}-27$$

Convert 27 to fraction \frac{81}{3}.

$$\frac{26}{3}-\frac{81}{3}$$

Since \frac{26}{3} and \frac{81}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{26-81}{3}$$

Subtract 81 from 26 to get -55.

$$-\frac{55}{3}$$

Factor

$$-\frac{55}{3} = -18\frac{1}{3} = -18.333333333333332$$