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a+b=-55 ab=21\times 26=546
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 21x^{2}+ax+bx+26. To find a and b, set up a system to be solved.
-1,-546 -2,-273 -3,-182 -6,-91 -7,-78 -13,-42 -14,-39 -21,-26
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 546.
-1-546=-547 -2-273=-275 -3-182=-185 -6-91=-97 -7-78=-85 -13-42=-55 -14-39=-53 -21-26=-47
Calculate the sum for each pair.
a=-42 b=-13
The solution is the pair that gives sum -55.
\left(21x^{2}-42x\right)+\left(-13x+26\right)
Rewrite 21x^{2}-55x+26 as \left(21x^{2}-42x\right)+\left(-13x+26\right).
21x\left(x-2\right)-13\left(x-2\right)
Factor out 21x in the first and -13 in the second group.
\left(x-2\right)\left(21x-13\right)
Factor out common term x-2 by using distributive property.
x=2 x=\frac{13}{21}
To find equation solutions, solve x-2=0 and 21x-13=0.
21x^{2}-55x+26=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-55\right)±\sqrt{\left(-55\right)^{2}-4\times 21\times 26}}{2\times 21}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 21 for a, -55 for b, and 26 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-55\right)±\sqrt{3025-4\times 21\times 26}}{2\times 21}
Square -55.
x=\frac{-\left(-55\right)±\sqrt{3025-84\times 26}}{2\times 21}
Multiply -4 times 21.
x=\frac{-\left(-55\right)±\sqrt{3025-2184}}{2\times 21}
Multiply -84 times 26.
x=\frac{-\left(-55\right)±\sqrt{841}}{2\times 21}
Add 3025 to -2184.
x=\frac{-\left(-55\right)±29}{2\times 21}
Take the square root of 841.
x=\frac{55±29}{2\times 21}
The opposite of -55 is 55.
x=\frac{55±29}{42}
Multiply 2 times 21.
x=\frac{84}{42}
Now solve the equation x=\frac{55±29}{42} when ± is plus. Add 55 to 29.
x=2
Divide 84 by 42.
x=\frac{26}{42}
Now solve the equation x=\frac{55±29}{42} when ± is minus. Subtract 29 from 55.
x=\frac{13}{21}
Reduce the fraction \frac{26}{42} to lowest terms by extracting and canceling out 2.
x=2 x=\frac{13}{21}
The equation is now solved.
21x^{2}-55x+26=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
21x^{2}-55x+26-26=-26
Subtract 26 from both sides of the equation.
21x^{2}-55x=-26
Subtracting 26 from itself leaves 0.
\frac{21x^{2}-55x}{21}=-\frac{26}{21}
Divide both sides by 21.
x^{2}-\frac{55}{21}x=-\frac{26}{21}
Dividing by 21 undoes the multiplication by 21.
x^{2}-\frac{55}{21}x+\left(-\frac{55}{42}\right)^{2}=-\frac{26}{21}+\left(-\frac{55}{42}\right)^{2}
Divide -\frac{55}{21}, the coefficient of the x term, by 2 to get -\frac{55}{42}. Then add the square of -\frac{55}{42} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-\frac{55}{21}x+\frac{3025}{1764}=-\frac{26}{21}+\frac{3025}{1764}
Square -\frac{55}{42} by squaring both the numerator and the denominator of the fraction.
x^{2}-\frac{55}{21}x+\frac{3025}{1764}=\frac{841}{1764}
Add -\frac{26}{21} to \frac{3025}{1764} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x-\frac{55}{42}\right)^{2}=\frac{841}{1764}
Factor x^{2}-\frac{55}{21}x+\frac{3025}{1764}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{55}{42}\right)^{2}}=\sqrt{\frac{841}{1764}}
Take the square root of both sides of the equation.
x-\frac{55}{42}=\frac{29}{42} x-\frac{55}{42}=-\frac{29}{42}
Simplify.
x=2 x=\frac{13}{21}
Add \frac{55}{42} to both sides of the equation.