Solve 205-[1200-(4^2-2*3)^3]:40

$$205 - [ 1200 - ( 4 ^ { 2 } - 2 \cdot 3 ) ^ { 3 } ] : 40$$

Evaluate

$$200$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$205-\frac{1200-\left(16-2\times 3\right)^{3}}{40}$$

Multiply 2 and 3 to get 6.

$$205-\frac{1200-\left(16-6\right)^{3}}{40}$$

Subtract 6 from 16 to get 10.

$$205-\frac{1200-10^{3}}{40}$$

Calculate 10 to the power of 3 and get 1000.

$$205-\frac{1200-1000}{40}$$

Subtract 1000 from 1200 to get 200.

$$205-\frac{200}{40}$$

Divide 200 by 40 to get 5.

$$205-5$$

Subtract 5 from 205 to get 200.

$$200$$

Factor

$$2^{3}\times 5^{2}$$