Solve 2017^0-8*2^-1-2^10div2^8

$$2017 ^ { 0 } - 8 \times 2 ^ { - 1 } - 2 ^ { 10 } \div 2 ^ { 8 }$$

Evaluate

$$-7$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 8 from 10 to get 2.

$$2017^{0}-8\times 2^{-1}-2^{2}$$

Calculate 2017 to the power of 0 and get 1.

$$1-8\times 2^{-1}-2^{2}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$1-8\times \frac{1}{2}-2^{2}$$

Multiply 8 and \frac{1}{2} to get 4.

$$1-4-2^{2}$$

Subtract 4 from 1 to get -3.

$$-3-2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$-3-4$$

Subtract 4 from -3 to get -7.

$$-7$$

Factor

$$-7$$