Solve 2000(1+x)^2=2335

$$2000 ( 1 + x ) ^ { 2 } = 2335$$

Solve for x

$$x=\frac{\sqrt{467}}{20}-1\approx 0.080509139$$

$$x=-\frac{\sqrt{467}}{20}-1\approx -2.080509139$$

Steps by Finding Square Root

Divide both sides by 2000.

$$\frac{2000\left(x+1\right)^{2}}{2000}=\frac{2335}{2000}$$

Dividing by 2000 undoes the multiplication by 2000.

$$\left(x+1\right)^{2}=\frac{2335}{2000}$$

Reduce the fraction \frac{2335}{2000} to lowest terms by extracting and canceling out 5.

$$\left(x+1\right)^{2}=\frac{467}{400}$$

Take the square root of both sides of the equation.

$$x+1=\frac{\sqrt{467}}{20} x+1=-\frac{\sqrt{467}}{20}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{\sqrt{467}}{20}-1 x+1-1=-\frac{\sqrt{467}}{20}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{\sqrt{467}}{20}-1 x=-\frac{\sqrt{467}}{20}-1$$