Solve 200x+110(10-x)geq1500

$$200 x + 110 ( 10 - x ) \geq 1500$$

Solve for x

$$x\geq \frac{40}{9}$$

Solution Steps

Use the distributive property to multiply 110 by 10-x.

$$200x+1100-110x\geq 1500$$

Combine 200x and -110x to get 90x.

$$90x+1100\geq 1500$$

Subtract 1100 from both sides.

$$90x\geq 1500-1100$$

Subtract 1100 from 1500 to get 400.

$$90x\geq 400$$

Divide both sides by 90. Since 90 is positive, the inequality direction remains the same.

$$x\geq \frac{400}{90}$$

Reduce the fraction \frac{400}{90} to lowest terms by extracting and canceling out 10.

$$x\geq \frac{40}{9}$$