Solve 200lceil(1+.08/12)-1rceil

$$200 \lceil (1+ \frac{ .08 }{ 12 } )-1 \rceil$$

Evaluate

$$200$$

Solution Steps

Expand \frac{0.08}{12} by multiplying both numerator and the denominator by 100.

$$200\lceil 1+\frac{8}{1200}-1\rceil$$

Reduce the fraction \frac{8}{1200} to lowest terms by extracting and canceling out 8.

$$200\lceil 1+\frac{1}{150}-1\rceil$$

Convert 1 to fraction \frac{150}{150}.

$$200\lceil \frac{150}{150}+\frac{1}{150}-1\rceil$$

Since \frac{150}{150} and \frac{1}{150} have the same denominator, add them by adding their numerators.

$$200\lceil \frac{150+1}{150}-1\rceil$$

Add 150 and 1 to get 151.

$$200\lceil \frac{151}{150}-1\rceil$$

Convert 1 to fraction \frac{150}{150}.

$$200\lceil \frac{151}{150}-\frac{150}{150}\rceil$$

Since \frac{151}{150} and \frac{150}{150} have the same denominator, subtract them by subtracting their numerators.

$$200\lceil \frac{151-150}{150}\rceil$$

Subtract 150 from 151 to get 1.

$$200\lceil \frac{1}{150}\rceil$$

Dividing 1 by 150 gives 0 and remainder 1. Rewrite \frac{1}{150} as 0+\frac{1}{150}.

$$200\lceil 0+\frac{1}{150}\rceil$$

The ceiling of a real number a is the smallest integer number greater than or equal to a. The ceiling of 0+\frac{1}{150} is 1.

$$200\times 1$$

Multiply 200 and 1 to get 200.

$$200$$

Factor

$$2^{3}\times 5^{2}$$