Solve 2001/3*(-1992/3)

$$200 \frac { 1 } { 3 } \times ( - 199 \frac { 2 } { 3 } )$$

Evaluate

$$-\frac{359999}{9}\approx -39999.888888889$$

Solution Steps

Multiply 200 and 3 to get 600.

$$\frac{600+1}{3}\left(-\frac{199\times 3+2}{3}\right)$$

Add 600 and 1 to get 601.

$$\frac{601}{3}\left(-\frac{199\times 3+2}{3}\right)$$

Multiply 199 and 3 to get 597.

$$\frac{601}{3}\left(-\frac{597+2}{3}\right)$$

Add 597 and 2 to get 599.

$$\frac{601}{3}\left(-\frac{599}{3}\right)$$

Multiply \frac{601}{3} times -\frac{599}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{601\left(-599\right)}{3\times 3}$$

Do the multiplications in the fraction \frac{601\left(-599\right)}{3\times 3}.

$$\frac{-359999}{9}$$

Fraction \frac{-359999}{9} can be rewritten as -\frac{359999}{9} by extracting the negative sign.

$$-\frac{359999}{9}$$

Factor

$$-\frac{359999}{9} = -39999\frac{8}{9} = -39999.88888888889$$