Solve 20xydivxy=

$$20 x y \div x y =$$

Evaluate

$$20y^{2}$$

Solution Steps

Cancel out x in both numerator and denominator.

$$20yy$$

Multiply y and y to get y^{2}.

$$20y^{2}$$

Differentiate w.r.t. y

$$40y$$

Steps Using Definition of a Derivative

Cancel out x in both numerator and denominator.

$$\frac{\mathrm{d}}{\mathrm{d}y}(20yy)$$

Multiply y and y to get y^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}y}(20y^{2})$$

The derivative of ax^{n} is nax^{n-1}.

$$2\times 20y^{2-1}$$

Multiply 2 times 20.

$$40y^{2-1}$$

Subtract 1 from 2.

$$40y^{1}$$

For any term t, t^{1}=t.

$$40y$$