Solve 20x+87leq100x-1

$$20 x + 87 \leq 100 x - 1$$

Solve for x

$$x\geq \frac{11}{10}$$

Solution Steps

Subtract 100x from both sides.

$$20x+87-100x\leq -1$$

Combine 20x and -100x to get -80x.

$$-80x+87\leq -1$$

Subtract 87 from both sides.

$$-80x\leq -1-87$$

Subtract 87 from -1 to get -88.

$$-80x\leq -88$$

Divide both sides by -80. Since -80 is negative, the inequality direction is changed.

$$x\geq \frac{-88}{-80}$$

Reduce the fraction \frac{-88}{-80} to lowest terms by extracting and canceling out -8.

$$x\geq \frac{11}{10}$$