Solve 2050/1.01+35/1.05^2=

$$20 \frac{ 50 }{ 1.01 } + \frac{ 35 }{ { 1.05 }^{ 2 } } =$$

Evaluate

$$\frac{644260}{6363}\approx 101.250982241$$

Solution Steps

Multiply 20 and 1.01 to get 20.2.

$$\frac{20.2+50}{1.01}+\frac{35}{1.05^{2}}$$

Add 20.2 and 50 to get 70.2.

$$\frac{70.2}{1.01}+\frac{35}{1.05^{2}}$$

Expand \frac{70.2}{1.01} by multiplying both numerator and the denominator by 100.

$$\frac{7020}{101}+\frac{35}{1.05^{2}}$$

Calculate 1.05 to the power of 2 and get 1.1025.

$$\frac{7020}{101}+\frac{35}{1.1025}$$

Expand \frac{35}{1.1025} by multiplying both numerator and the denominator by 10000.

$$\frac{7020}{101}+\frac{350000}{11025}$$

Reduce the fraction \frac{350000}{11025} to lowest terms by extracting and canceling out 175.

$$\frac{7020}{101}+\frac{2000}{63}$$

Least common multiple of 101 and 63 is 6363. Convert \frac{7020}{101} and \frac{2000}{63} to fractions with denominator 6363.

$$\frac{442260}{6363}+\frac{202000}{6363}$$

Since \frac{442260}{6363} and \frac{202000}{6363} have the same denominator, add them by adding their numerators.

$$\frac{442260+202000}{6363}$$

Add 442260 and 202000 to get 644260.

$$\frac{644260}{6363}$$

Factor

$$\frac{5 \cdot 32213 \cdot 2 ^ {2}}{7 \cdot 101 \cdot 3 ^ {2}} = 101\frac{1597}{6363} = 101.25098224108125$$