Solve 201/3+4+76/7

$$20 \frac { 1 } { 3 } + 4 + 7 \frac { 6 } { 7 }$$

Evaluate

$$\frac{676}{21}\approx 32.19047619$$

Solution Steps

Multiply 20 and 3 to get 60.

$$\frac{60+1}{3}+4+\frac{7\times 7+6}{7}$$

Add 60 and 1 to get 61.

$$\frac{61}{3}+4+\frac{7\times 7+6}{7}$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{61}{3}+\frac{12}{3}+\frac{7\times 7+6}{7}$$

Since \frac{61}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$\frac{61+12}{3}+\frac{7\times 7+6}{7}$$

Add 61 and 12 to get 73.

$$\frac{73}{3}+\frac{7\times 7+6}{7}$$

Multiply 7 and 7 to get 49.

$$\frac{73}{3}+\frac{49+6}{7}$$

Add 49 and 6 to get 55.

$$\frac{73}{3}+\frac{55}{7}$$

Least common multiple of 3 and 7 is 21. Convert \frac{73}{3} and \frac{55}{7} to fractions with denominator 21.

$$\frac{511}{21}+\frac{165}{21}$$

Since \frac{511}{21} and \frac{165}{21} have the same denominator, add them by adding their numerators.

$$\frac{511+165}{21}$$

Add 511 and 165 to get 676.

$$\frac{676}{21}$$

Factor

$$\frac{2 ^ {2} \cdot 13 ^ {2}}{3 \cdot 7} = 32\frac{4}{21} = 32.19047619047619$$