20 \% x+30 \% y=25 \%
Solve for x
x=-\frac{3y}{2}+\frac{5}{4}
Solve for y
y=-\frac{2x}{3}+\frac{5}{6}
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\frac{1}{5}x+\frac{30}{100}y=\frac{25}{100}
Reduce the fraction \frac{20}{100} to lowest terms by extracting and canceling out 20.
\frac{1}{5}x+\frac{3}{10}y=\frac{25}{100}
Reduce the fraction \frac{30}{100} to lowest terms by extracting and canceling out 10.
\frac{1}{5}x+\frac{3}{10}y=\frac{1}{4}
Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.
\frac{1}{5}x=\frac{1}{4}-\frac{3}{10}y
Subtract \frac{3}{10}y from both sides.
\frac{1}{5}x=-\frac{3y}{10}+\frac{1}{4}
The equation is in standard form.
\frac{\frac{1}{5}x}{\frac{1}{5}}=\frac{-\frac{3y}{10}+\frac{1}{4}}{\frac{1}{5}}
Multiply both sides by 5.
x=\frac{-\frac{3y}{10}+\frac{1}{4}}{\frac{1}{5}}
Dividing by \frac{1}{5} undoes the multiplication by \frac{1}{5}.
x=-\frac{3y}{2}+\frac{5}{4}
Divide \frac{1}{4}-\frac{3y}{10} by \frac{1}{5} by multiplying \frac{1}{4}-\frac{3y}{10} by the reciprocal of \frac{1}{5}.
\frac{1}{5}x+\frac{30}{100}y=\frac{25}{100}
Reduce the fraction \frac{20}{100} to lowest terms by extracting and canceling out 20.
\frac{1}{5}x+\frac{3}{10}y=\frac{25}{100}
Reduce the fraction \frac{30}{100} to lowest terms by extracting and canceling out 10.
\frac{1}{5}x+\frac{3}{10}y=\frac{1}{4}
Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.
\frac{3}{10}y=\frac{1}{4}-\frac{1}{5}x
Subtract \frac{1}{5}x from both sides.
\frac{3}{10}y=-\frac{x}{5}+\frac{1}{4}
The equation is in standard form.
\frac{\frac{3}{10}y}{\frac{3}{10}}=\frac{-\frac{x}{5}+\frac{1}{4}}{\frac{3}{10}}
Divide both sides of the equation by \frac{3}{10}, which is the same as multiplying both sides by the reciprocal of the fraction.
y=\frac{-\frac{x}{5}+\frac{1}{4}}{\frac{3}{10}}
Dividing by \frac{3}{10} undoes the multiplication by \frac{3}{10}.
y=-\frac{2x}{3}+\frac{5}{6}
Divide \frac{1}{4}-\frac{x}{5} by \frac{3}{10} by multiplying \frac{1}{4}-\frac{x}{5} by the reciprocal of \frac{3}{10}.
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