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20^{8v}=35.5
Use the rules of exponents and logarithms to solve the equation.
\log(20^{8v})=\log(35.5)
Take the logarithm of both sides of the equation.
8v\log(20)=\log(35.5)
The logarithm of a number raised to a power is the power times the logarithm of the number.
8v=\frac{\log(35.5)}{\log(20)}
Divide both sides by \log(20).
8v=\log_{20}\left(35.5\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
v=\frac{\ln(\frac{71}{2})}{8\ln(20)}
Divide both sides by 8.