Solve 20=1/2(3+b)*5

$$20 = \frac { 1 } { 2 } ( 3 + b ) \times 5$$

Solve for b

$$b=5$$

Steps for Solving Linear Equation

Multiply \frac{1}{2} and 5 to get \frac{5}{2}.

$$20=\frac{5}{2}\left(3+b\right)$$

Use the distributive property to multiply \frac{5}{2} by 3+b.

$$20=\frac{5}{2}\times 3+\frac{5}{2}b$$

Express \frac{5}{2}\times 3 as a single fraction.

$$20=\frac{5\times 3}{2}+\frac{5}{2}b$$

Multiply 5 and 3 to get 15.

$$20=\frac{15}{2}+\frac{5}{2}b$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{15}{2}+\frac{5}{2}b=20$$

Subtract \frac{15}{2} from both sides.

$$\frac{5}{2}b=20-\frac{15}{2}$$

Convert 20 to fraction \frac{40}{2}.

$$\frac{5}{2}b=\frac{40}{2}-\frac{15}{2}$$

Since \frac{40}{2} and \frac{15}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5}{2}b=\frac{40-15}{2}$$

Subtract 15 from 40 to get 25.

$$\frac{5}{2}b=\frac{25}{2}$$

Multiply both sides by \frac{2}{5}, the reciprocal of \frac{5}{2}.

$$b=\frac{25}{2}\times \frac{2}{5}$$

Multiply \frac{25}{2} times \frac{2}{5} by multiplying numerator times numerator and denominator times denominator.

$$b=\frac{25\times 2}{2\times 5}$$

Cancel out 2 in both numerator and denominator.

$$b=\frac{25}{5}$$

Divide 25 by 5 to get 5.

$$b=5$$