Solve 2.6x+3.5y=55

$$2.6 x + 3.5 y = 55$$

Solve for x

$$x=-\frac{35y}{26}+\frac{275}{13}$$

Steps for Solving Linear Equation

Subtract 3.5y from both sides.

$$2.6x=55-3.5y$$

The equation is in standard form.

$$2.6x=-\frac{7y}{2}+55$$

Divide both sides of the equation by 2.6, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{2.6x}{2.6}=\frac{-\frac{7y}{2}+55}{2.6}$$

Dividing by 2.6 undoes the multiplication by 2.6.

$$x=\frac{-\frac{7y}{2}+55}{2.6}$$

Divide 55-\frac{7y}{2} by 2.6 by multiplying 55-\frac{7y}{2} by the reciprocal of 2.6.

$$x=-\frac{35y}{26}+\frac{275}{13}$$

Solve for y

$$y=-\frac{26x}{35}+\frac{110}{7}$$

Steps for Solving Linear Equation

Subtract 2.6x from both sides.

$$3.5y=55-2.6x$$

The equation is in standard form.

$$3.5y=-\frac{13x}{5}+55$$

Divide both sides of the equation by 3.5, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{3.5y}{3.5}=\frac{-\frac{13x}{5}+55}{3.5}$$

Dividing by 3.5 undoes the multiplication by 3.5.

$$y=\frac{-\frac{13x}{5}+55}{3.5}$$

Divide 55-\frac{13x}{5} by 3.5 by multiplying 55-\frac{13x}{5} by the reciprocal of 3.5.

$$y=-\frac{26x}{35}+\frac{110}{7}$$