Solve 2-x^24sqrt{4}

$$2- { x }^{ 2 } 4 \sqrt{ 4 }$$

Evaluate

$$2-8x^{2}$$

Solution Steps

Calculate the square root of 4 and get 2.

$$2-4x^{2}\times 2$$

Multiply 4 and 2 to get 8.

$$2-8x^{2}$$

Factor

$$2\left(-2x-1\right)\left(2x-1\right)$$

Solution Steps

Calculate the square root of 4 and get 2.

$$factor(2-4x^{2}\times 2)$$

Multiply 4 and 2 to get 8.

$$factor(2-8x^{2})$$

Factor out 2.

$$2\left(1-4x^{2}\right)$$

Consider 1-4x^{2}. Rewrite 1-4x^{2} as 1^{2}-\left(2x\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(1-2x\right)\left(1+2x\right)$$

Reorder the terms.

$$\left(-2x+1\right)\left(2x+1\right)$$

Rewrite the complete factored expression.

$$2\left(-2x+1\right)\left(2x+1\right)$$