Solve 2(2x+48/96)=13

$$2(2x+ \frac{ 48 }{ 96 } )=13$$

Solve for x

$$x=3$$

Steps for Solving Linear Equation

Divide both sides by 2.

$$2x+\frac{48}{96}=\frac{13}{2}$$

Reduce the fraction \frac{48}{96} to lowest terms by extracting and canceling out 48.

$$2x+\frac{1}{2}=\frac{13}{2}$$

Subtract \frac{1}{2} from both sides.

$$2x=\frac{13}{2}-\frac{1}{2}$$

Since \frac{13}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$2x=\frac{13-1}{2}$$

Subtract 1 from 13 to get 12.

$$2x=\frac{12}{2}$$

Divide 12 by 2 to get 6.

$$2x=6$$

Divide both sides by 2.

$$x=\frac{6}{2}$$

Divide 6 by 2 to get 3.

$$x=3$$