Solve 2(x^2-4x)-2x^2+12=0

$$2( { x }^{ 2 } -4x)-2 { x }^{ 2 } +12=0$$

Solve for x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by x^{2}-4x.

$$2x^{2}-8x-2x^{2}+12=0$$

Combine 2x^{2} and -2x^{2} to get 0.

$$-8x+12=0$$

Subtract 12 from both sides. Anything subtracted from zero gives its negation.

$$-8x=-12$$

Divide both sides by -8.

$$x=\frac{-12}{-8}$$

Reduce the fraction \frac{-12}{-8} to lowest terms by extracting and canceling out -4.

$$x=\frac{3}{2}$$